## Problem Description :

Write a program in Java that generates first N hexagonal numbers.

 First N Hexagonal numbers

## Concept :

We can generate Nth hexagonal number using below formula.
N(2N-1)
For example - first 6 hexagonal numbers are 1, 6, 15, 28, 45, 66.

 Hexagonal Numbers

## Java Program :

```package com.javamultiplex.number;

import java.util.Scanner;

/**
*
* @author Rohit Agarwal
* @category Number Questions
* @level Basic
* @problem How to generate first N hexagonal numbers?
*
*/
public class HexagonalNumbers {

public static void main(String[] args) {

Scanner input = null;
try {
input = new Scanner(System.in);
System.out.println("Enter value of N : ");
int limit = input.nextInt();
int hexagonal = 0;
System.out.println("Hexagonal numbers are : ");
for (int n = 1; n <= limit; n++) {
hexagonal = n * (2 * n - 1);
System.out.print(hexagonal + " ");
}
} finally {
if (input != null) {
input.close();
}
}

}

}

```

## Output :

 Output - How to generate first n hexagonal numbers in Java?

## References :

https://en.wikipedia.org/wiki/Hexagonal_number

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Tags : Hexagonal numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement.