How to generate first N Hexagonal numbers in Java?



Problem Description :


Write a program in Java that generates first N hexagonal numbers.

Java program that generates first n hexagonal numbers.
First N Hexagonal numbers


Concept
:


We can generate Nth hexagonal number using below formula.
N(2N-1)
For example - first 6 hexagonal numbers are 1, 6, 15, 28, 45, 66.

What is Hexagonal number?
Hexagonal Numbers

Java Program :


package com.javamultiplex.number;

import java.util.Scanner;

/**
 * 
 * @author Rohit Agarwal
 * @category Number Questions
 * @level Basic
 * @problem How to generate first N hexagonal numbers?
 *
 */
public class HexagonalNumbers {

 public static void main(String[] args) {

  Scanner input = null;
  try {
   input = new Scanner(System.in);
   System.out.println("Enter value of N : ");
   int limit = input.nextInt();
   int hexagonal = 0;
   System.out.println("Hexagonal numbers are : ");
   for (int n = 1; n <= limit; n++) {
    hexagonal = n * (2 * n - 1);
    System.out.print(hexagonal + " ");
   }
  } finally {
   if (input != null) {
    input.close();
   }
  }

 }

}


Output :


Output of Java program that generates first n hexagonal numbers.
Output - How to generate first n hexagonal numbers in Java?

References :


https://en.wikipedia.org/wiki/Hexagonal_number

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Tags : Hexagonal numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement.

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How to generate first N Hexagonal numbers in Java? How to generate first N Hexagonal numbers in Java? Reviewed by Rohit Agarwal on 1/30/2017 Rating: 5

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