# How to generate first N Hexagonal numbers in Java?

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__Problem Description__ :

Write a program in Java that generates first N hexagonal numbers.

First N Hexagonal numbers |

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Concept :

Concept

We can generate Nth hexagonal number using below formula.

**N(2N-1)**

__For example__- first 6 hexagonal numbers are 1, 6, 15, 28, 45, 66.

Hexagonal Numbers |

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__Java Program__ :

package com.javamultiplex.number; import java.util.Scanner; /** * * @author Rohit Agarwal * @category Number Questions * @level Basic * @problem How to generate first N hexagonal numbers? * */ public class HexagonalNumbers { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter value of N : "); int limit = input.nextInt(); int hexagonal = 0; System.out.println("Hexagonal numbers are : "); for (int n = 1; n <= limit; n++) { hexagonal = n * (2 * n - 1); System.out.print(hexagonal + " "); } } finally { if (input != null) { input.close(); } } } }

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__Output__ :

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__References__ :

Thank you friends, I hope you have clearly understood the solution of this problem. If you have any doubt, suggestion or query please feel free to comment below. You can also discuss this solution in our forum.

**Tags : Hexagonal numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement.**

How to generate first N Hexagonal numbers in Java?
Reviewed by Rohit Agarwal
on
1/30/2017
Rating:

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