## Problem Description :

Write a program in Java that generates first N pentagonal numbers.

 First N Pentagonal numbers

## Concept :

We can generate Nth pentagonal number using below formula.
N(3N-1)/2
For example -  first 6 pentagonal numbers are 1, 5, 12, 22, 35, 51.

 Pentagonal Numbers

## Java Program :

```package com.javamultiplex.number;

import java.util.Scanner;

/**
*
* @author Rohit Agarwal
* @category Number Questions
* @level Basic
* @problem How to generate first N pentagonal numbers?
*
*/
public class PentagonalNumbers {

public static void main(String[] args) {

Scanner input = null;
try {
input = new Scanner(System.in);
System.out.println("Enter value of N : ");
int limit = input.nextInt();
int pentagonal = 0;
System.out.println("Pentagonal numbers are : ");
for (int n = 1; n <= limit; n++) {
pentagonal = (n * (3 * n - 1)) / 2;
System.out.print(pentagonal + " ");
}
} finally {
if (input != null) {
input.close();
}
}

}
}

```

## Output :

 Output - How to generate first n pentagonal numbers in Java?

## References :

https://en.wikipedia.org/wiki/Pentagonal_number

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Tags : Pentagonal numbers in Java, Solution in Java, Mathematics problems, for loop, if else statement.