# How to check whether given number is Armstrong or not in Java?

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__Problem Description__ :

Write a program in Java that checks whether given number is Armstrong or not.

Number is Armstrong or not? |

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Concept :

Concept

Armstrong number is a number that is equal to the sum of cubes of its digits. For example 153 because 153 = 1*1*1 + 5*5*5 + 3*3*3.

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__Java Program__ :

package com.javamultiplex.number; import java.util.Scanner; public class ArmstrongNumber { public static void main(String[] args) { Scanner input = null; try { input = new Scanner(System.in); System.out.println("Enter number : "); String num = input.next(); if (isValidNumber(num)) { int length = num.length(); int temp = 0, sum = 0; for (int i = 0; i < length; i++) { // Converting char to int. temp = num.charAt(i) - 48; sum += temp * temp * temp; } // Converting int to String. String finalSum = String.valueOf(sum); if (num.equals(finalSum)) { System.out.println(num + " is an Armstrong number."); } else { System.out.println(num + " is not an Armstrong number."); } } else { System.out.println("Please enter valid number."); } } finally { if (input != null) { input.close(); } } } private static boolean isValidNumber(String num) { String pattern = "^[0-9]+$"; boolean result = false; if (num.matches(pattern)) { result = true; } return result; } }

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__Output__ :

## Case 1 :

Given number is not Armstrong |

### Case 2 :

Given number is Armstrong |

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__References__ :

http://docs.oracle.com/javase/7/docs/api/java/lang/String.html

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**Tags : Number Problems, Armstrong Number, if else statement, for loop, String, Regular expressions, Mathematics Problem.**

How to check whether given number is Armstrong or not in Java?
Reviewed by Rohit Agarwal
on
3/10/2017
Rating:

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