# Project Euler | Problem 9 | Special Pythagorean Triplet

##
__Problem Description__ :

For example, 32 + 42 = 9 + 16 = 25 = 52. There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.

##
__Concept__ :

We have following two equations.

1) a^2+b^2=c^2

2) a+b+c=1000

on solving these equations mathematically.

1<=a<=999

b=(1000^2-(2*a*1000))/(2*(1000-a))

c=1000-b-a

##
__Java Program__ :

##
__Output__ :

##
__References__ :

https://en.wikipedia.org/wiki/Pythagorean_triple

https://docs.oracle.com/javase/7/docs/api/java/lang/Math.html

Thank you friends, I hope you have clearly understood the solution of this problem. If you have any doubt, suggestion or query please feel free to comment below. You can also discuss this solution in our forum.

**Tags : Project Euler Problem 9 solution in Java, Mathematics problems, Special Pythagorean Triplet, for loop, if else statement.**

Project Euler | Problem 9 | Special Pythagorean Triplet
Reviewed by Unknown
on
3/10/2017
Rating:

## No comments:

Please provide your valuable comments. If you have any suggestion please share with me I will work on it and if you have any question or doubt please ask, don't hesitate. I am your friend, i will clarify all your doubts.